Oracleの1Z0-805試験の準備をしていたら、JapanCertは貴方が夢を実現することにヘルプを与えます。 JapanCertのOracleの1Z0-805試験トレーニング資料は高品質のトレーニング資料で、１００パーセントの合格率を保証できます。もしあなたが適当な時間を持って勉強できるのなら、JapanCertのOracleの1Z0-805試験トレーニング資料を選びましょう。この資料を手に入れたら、楽に試験の準備をすることができます。
JapanCertを通じて最新のOracleの1Z0-805試験の問題と解答早めにを持てて、弊社の問題集があればきっと君の強い力になります。
1Z0-805認定試験を受験したいですか。1Z0-805認証資格を取得したいですか。試験に準備する時間が足りないあなたは、どうやって試験に合格できますか。しようがないわけではないです。短時間の準備でも楽に試験に合格することができるようになりますよ。それでは、どのようにすればそれを達成できますか。実は方法がとても簡単です。すなわちJapanCertの1Z0-805問題集を利用して試験の準備をすることです。
試験番号：1Z0-805問題集
試験科目：Oracle 「Upgrade to Java SE 7 Programmer」
最近更新時間：2014-04-16
問題と解答：90
JapanCertは正確な選択を与えて、君の悩みを減らして、もし早くてOracle 1Z0-805認証をとりたければ、早くてJapanCertをショッピングカートに入れましょう。あなたにとても良い指導を確保できて、試験に合格するのを助けって、JapanCertからすぐにあなたの通行証をとります。
JapanCertのIT専門家たちは受験生の皆さんのニーズを満たすように彼らの豊富な知識と経験を活かして試験トレーニング資料の品質をずっと高めています。受験生の皆さんが一回でOracleの1Z0-805試験に合格することを保証します。JapanCertの製品を購入したら、あなたはいつでも最新かつ最正確な試験情報を得ることができます。JapanCertの資料のカバー率が高くて、受験生に便宜を与えられます。それに、問題集の合格率が１００パーセントに達するのですから、あなたは安心に試験を受けることができます。
JapanCertが提供した研修ツールはOracleの1Z0-805の認定試験に向けて学習資料やシミュレーション訓練宿題で、重要なのは試験に近い練習問題と解答を提供いたします。JapanCert を選ばれば短時間にITの知識を身につけることができて、高い点数をとられます。
購入前にお試し,私たちの試験の質問と回答のいずれかの無料サンプルをダウンロード：http://www.japancert.com/1Z0-805.html
NO.1 Given the code fragment:
public static void main(String[] args) {
String source = "d:\\company\\info.txt";
String dest = "d:\\company\\emp\\info.txt";
//insert code fragment here Line **
} catch (IOException e) {
System.err.println ("Caught IOException: " + e.getmessage();
}
}
Which two try statements, when inserted at line **, enable the code to successfully move the file info.txt to
the destination directory, even if a file by the same name already exists in the destination directory?
A. try {FileChannel in = new FileInputStream(source).getChannel(); FileChannel out = new
FileOutputStream(dest).getChannel (); in.transferTo (0, in.size(), out);
B. try {Files.copy(Paths.get(source), Paths.get(dest)); Files.delete(Paths.get(source));
C. try {Files.copy(Paths.get(source), Paths.get(dest)); Files.delete(Paths.get(source));
D. try {Files.move(Paths.get(source),Paths.get(dest));
E. try {BufferedReader br = Files.newBufferedReader(Paths.get(source), Charset.forName ("UTF8"));
BufferedWriter bw = Files.newBufferedWriter (Paths.get(dest), Charset.forName ("UTF-8")); String record
= ""; while ((record = br.readLine()) != null){ bw.write (record); bw.newLine(); }
Files.delete(Paths.get(source));
Answer: B,D
Oracle認定資格 1Z0-805 1Z0-805
NO.2 What design pattern does the Drivermanager.getconnection () method characterize?
A. DAO
B. Factory
C. Singleton
D. composition
Answer: B
Oracle問題集 1Z0-805 1Z0-805問題集
NO.3 Which statement is true about the take method defined in the WatchService interface?
A. Retrieves and removes the next watch key, or returns null of none are present.
B. Retrieves and removes the next watch key. If a queued key is not immediately available, the program
waits for the specified wait time.
C. Retrieves and removes the next watch key: waits if no key is yet present.
D. Retrieves and removes all pending events for the watch key, returning a list of the events that were
retrieved.
Answer: C
Oracle認定試験 1Z0-805 1Z0-805過去問
NO.4 Which two statements are true about the walkFileTree method of the files class?
A. The file tree traversal is breadth-first with the given FileVisitor invoked for each file encountered.
B. If the file is a directory, and if that directory could not be opened, the postVisitFileFailed method is
invoked with the I/O exception.
C. The maxDepth parameter s value is the maximum number of directories to visit.
D. By default, symbolic links are not automatically followed by the method.
Answer: C,D
Oracle認定試験 1Z0-805練習問題 1Z0-805 1Z0-805認証試験 1Z0-805認定試験
NO.5 Given the code fragment:
List<Person> pList = new CopyOnWriteArrayList<Person>();
Which statement is true?
A. Read access to the List should be synchronized.
B. Write access to the List should be synchronized.
C. Person objects retrieved from the List are thread-safe.
D. A Person object retrieved from the List is copied when written to.
E. Multiple threads can safely delete Person objects from the List.
Answer: C
Oracle 1Z0-805 1Z0-805問題集
NO.6 Given:
import java.util.*; public class StringApp { public static void main (String [] args) { Set <String> set = new
TreeSet <> (); set.add("X"); set.add("Y"); set.add("X"); set.add("Y"); set.add("X"); Iterator <String> it =
set.iterator (); int count = 0; while (it.hasNext()) { switch (it.next()){ case "X": System.out.print("X "); break;
case "Y": System.out.print("Y "); break; } count++; } System.out.println ("\ncount = " + count); } }
What is the result?
A. X X Y X Y count = 5
B. X Y X Y count = 4
C. X Y count = s
D. X Y count = 2
Answer: D
Oracle 1Z0-805 1Z0-805 1Z0-805
NO.7 Given the code fragment:
private static void copyContents (File source, File target) {
try {inputStream fis = new FileInputStream(source);
outputStream fos = new FileOutputStream (target);
byte [] buf = new byte [8192]; int i;
while ((i = fis.read(buf)) != -1) {
fos.write (buf, 0, i);
}
//insert code fragment here. Line **
System.out.println ("Successfully copied");
}
Which code fragments, when inserted independently at line **, enable the code to compile?
A. }catch (IOException | NoSuchFileException e) { System.out.println(e); }
B. } catch (IOException | IndexOutOfBoundException e) { System.out.println(e); }
C. } catch (Exception | IOException | FileNotFoundException e ) { System.out.println(e); }
D. } catch (NoSuchFileException e ) { System.out.println(e); }
E. } catch (InvalidPathException | IOException e) { System.out.println(e); }
Answer: B,D,E
Oracle 1Z0-805 1Z0-805練習問題
NO.8 Given three resource bundles with these values set for menu1: ( The default resource bundle is
written in US English.)
English US resource Bundle Menu1 = small
French resource Bundle Menu1 = petit
Chinese Resource Bundle Menu = 1
And given the code fragment:
Locale.setDefault (new Locale("es", "ES")); // Set default to Spanish and Spain loc1 = Locale.getDefault();
ResourceBundle messages = ResourceBundle.getBundle ("messageBundle", loc1); System.out.println
(messages.getString("menu1")); What is the result?
A. No message is printed
B. petit
C. :
D. Small
E. A runtime error is produced
Answer: E
Oracle 1Z0-805認定試験 1Z0-805 1Z0-805
NO.9 Given the code fragment: public class Test {
public static void main (String [] args) {
Path path1 = Paths.get("D:\\sys\\asm\\.\\data\\..\\..\\mfg\\production.log");
System.out.println(path1.normalize());
System.out.println(path1.getNameCount());
}
}
What is the result?
A. D:\sys\mfg\production.log 8
B. D:\\sys\\asm\\.\\data\\. . \\mfg\\production.log 6
C. D: \\sys\\asm\\.\\data\\. . \\mfg\\production.log 8
D. D: \sys\mfg\production.log 4
E. D: \\ sys\\asm\\data\\mfg\\production.log 6
Answer: A
Oracle問題集 1Z0-805 1Z0-805問題集 1Z0-805
NO.10 Given the code fragment:
dataFormat df;
Which statement defines a new DataFormat object that displays the default date format for the UK
Locale?
A. df = DateFormat.getDateInstance (DateFormat.DEFAULT, Locale(UK));
B. df = DateFormat.getDateInstance (DateFormat.DEFAULT, UK);
C. df = DateFormat.getDateInstance (DateFormat.DEFAULT, Locale.UK);
D. df = new DateFormat.getDataInstance (DataFormat.DEFAULT, Locale.UK);
E. df = new DateFormat.getDateInstance (DateFormat.DEFAULT, Locale(UK));
Answer: C
Oracle問題集 1Z0-805過去問 1Z0-805認証試験 1Z0-805
NO.11 Given the following code fragment:
public class Calc {
public static void main (String [] args) {
//* insert code here Line ** System.out.print("The decimal value is" + var);
}
}
Which three code fragments, when inserted independently at line **, enable the code to compile/
A. int var = 0b_1001;
B. long var = 0b100_01L;
C. float var = 0b10_01;
D. float var = 0b10_01F;
E. double var = 0b10_01;
F. double var = 0b10_01D;
Answer: B,C,E
Oracle認定証 1Z0-805過去問 1Z0-805参考書 1Z0-805参考書 1Z0-805 1Z0-805問題集
NO.12 You are using a database from XY/Data. What is a prerequisite for connecting to the database using a
JDBC 4.0 driver from XY/Data?
A. Use the JDBC DriverManager.loadDriver method.
B. Put the XY/data driver into the classpath of your application.
C. Create an instance of the XY/Data driver class using the new keyword.
D. Create an Implementation of DriverManager that extends the XY/Data driver
Answer: B
Oracle 1Z0-805 1Z0-805認定試験 1Z0-805練習問題 1Z0-805練習問題 1Z0-805
NO.13 Which code fragments print 1?
A. String arr [] = {"1", "2", "3"}; List <? extendsString > arrList = new LinkedList <> (Arrays.asList (arr));
System.out.println (arrList.get (0));
B. String arr [] = {"1", "2", "3"}; List <Integer> arrList = new LinkedList <> (Arrays.asList (arr));
System.out.println (arrList.get (0));
C. String arr [] = {"1", "2", "3"}; List <?> arrList = new LinkedList <> (Arrays.asList (arr)); System.out.println
(arrList.get (0));
D. String arr [] = {"1","2","3"}; List <?> arrList = new LinkedList <?>(Arrays.asList (arr)); System.out.println
(arrList.get (0));
E. String arr [] = {"1","2","3"}; List <Integer> extendsString > arrList =new LinkedList <Integer>
(Arrays.asList (arr)); System.out.println (arrList.get (0));
Answer: A,C
Oracle認証試験 1Z0-805 1Z0-805 1Z0-805問題集
NO.14 Given the fragment:
public class CustomerApplication {
public static void main (String [] args) {
CustomerDAO custDao = new CustomerDAOMemoryImp1 ();
// . . . other methods
} }
Which two valid alternatives to line 3 would decouple this application from a specific implementation of
customerDAO?
A. CustomerDAO custDao = new customerDAO();
B. CustomerDAO custDao = (CustomerDAO) new object();
C. CustomerDAO custDao = CustomerDAO.getInstance();
D. CustomerDAO custDao = (CustomerDAO) new CustomerDAOmemoryImp1();
E. CustomerDAO custDao = CustomerDAOFactory.getInstance();
Answer: C,E
Oracle認定資格 1Z0-805認定証 1Z0-805 1Z0-805 1Z0-805認証試験
NO.15 Given a resource bundle MessageBundle, what is the name of the default bundle file?
A. MessageBundle.profile
B. MessageBundle.xml
C. MessageBundle.java
D. MessageBundle.properties
Answer: D
Oracle 1Z0-805 1Z0-805認定試験 1Z0-805参考書 1Z0-805 1Z0-805
JapanCertは最新の100-101問題集と高品質の648-385問題と回答を提供します。JapanCertのMB5-854 VCEテストエンジンとVCAW510試験ガイドはあなたが一回で試験に合格するのを助けることができます。高品質のC_TERP10_65 PDFトレーニング教材は、あなたがより迅速かつ簡単に試験に合格することを100％保証します。試験に合格して認証資格を取るのはそのような簡単なことです。
没有评论:
发表评论